Accenture Pattern Research 2025 | Previous Year Question Papers

Accenture Pattern Research 2025 : In-depth analysis of every Accenture question from the previous year will be covered in this extensive post, which is especially designed for individuals hoping to succeed in the 2024 hiring process. Our conversation will include a comprehensive analysis of the questions raised in previous years, providing perspectives and methods to address each one successfully. From behavioral evaluations to technical questions, our goal is to give you the skills and self-assurance you need to ace your next interview. This breakdown will be a useful tool for you as you get ready to join one of the top consulting and technology companies, regardless of whether you are a recent graduate or an experienced professional looking for new opportunities.

Assessment TypeSectionNumber of QuestionsTime (Minutes)
Cognitive AssessmentEnglish Ability1790 (Shared)
Critical Reasoning and Problem Solving1890 (Shared)
Abstract Reasoning1590 (Shared)
Technical AssessmentCommon Applications & MS Office1290 (Shared)
Pseudocode1890 (Shared)
Networking Security & Cloud1090 (Shared)
Coding AssesmentCoding and Programming Fundamentals (C, C++, .NET, Java, Python)245

Accenture Previous Year Question 2024 English Ability:

TopicsNumber of QuestionsDifficultyImportance
Synonyms & Antonyms3-4MediumHigh
Error Detection / Sentence Correction3-4MediumHigh
Para Jumbles2MediumMedium
Reading Comprehension3HighHigh
Sentence Completion / Fill in the Blanks2-3LowMedium
Sentence Improvement2-3LowM

Accenture Previous Year Question 2024 Critical Reasoning and Problem Solving:

TopicsNumber of QuestionsDifficultyImportance
Data Arrangements7-8HighHigh
Flow Chart2-3MediumHigh
Data Sufficiency1-2MediumMedium
Argument & Assumption2-3MediumMedium
Syllogisms2-3MediumMedium
Statement Conclusion2-3MediumMedium

Accenture Previous Year Question 2024 Abstract Reasoning:

TopicsNumber of QuestionsDifficultyImportance
Number and Letter Series3-4HighHigh
Odd Man Out2-3HighHigh
Analogies2-3HighHigh
Coding and Decoding3-4HighHigh
Visual Reasoning4-5MediumMedium

Accenture Previous Year Question 2024 Common Applications & MS Office:

TopicsNumber of QuestionsDifficultyImportance
MS Office (Word, PowerPoint, Excel, Outlook)2-3MediumHigh
Browsers’ Fundamentals2MediumHigh
Shortcut Keys2-3MediumHigh
Command Prompt2-3LowMedium
Working Flow of Keys2MediumMedium

Accenture Previous Year Question 2024 Pseudocode:

TopicsNumber of QuestionsDifficultyImportance
Programming FundamentalsPart of 18 questionsHighHigh
LoopingPart of 18 questionsHighHigh
ArraysPart of 18 questionsHighHigh
RecursionPart of 18 questionsMediumHigh
FunctionPart of 18 questionsHighHigh
Bitwise OperatorsPart of 18 questionsMediumMedium
Increment & Decrement OperatorsPart of 18 questionsLowMedium
Conditional StatementsPart of 18 questionsMediumHigh
Basics of Data StructuresPart of 18 questionsHighHigh

Accenture Previous Year Question 2024 Networl Security & Cloud:

TopicsNumber of QuestionsDifficultyImportance
Basics of NetworkingAmong the 10 key questionsMediumHigh
Network SecurityAmong the 10 key questionsHighHigh
Encryption Standards & AlgorithmsAmong the 10 key questionsHighHigh
Network Security DevicesAmong the 10 key questionsHighHigh
Attack TypesAmong the 10 key questionsHighHigh
FirewallsAmong the 10 key questionsMediumMedium
Fundamentals of Cloud ComputingAmong the 10 key questionsMediumHigh
Client-Server ArchitectureAmong the 10 key questionsMediumHigh
Cloud Data CentersAmong the 10 key questionsMediumHigh
Cloud Service ProvidersAmong the 10 key questionsMediumHigh
Cloud Service PlatformsAmong the 10 key questionsMediumHigh

Accenture Previous Year Question 2024 Coding:

TopicsNumber of QuestionsDifficultyImportance
Basics of Programming2 (45-Minute Time Limit)HighHigh
Input & Output ConceptsIntegrated within the primary 2 questionsHighHigh
Flow ControlEmbedded in the core 2 questionsHighHigh
Conditional LoopingPart of the fundamental 2 questionsHighHigh
ArraysCovered within the 2 main questionsHighHigh
FunctionsKey topic within the 2 questionsHighHigh
StringsA focus area within the 2 questionsMediumHigh
Data Types & OperatorsEssential part of the primary 2MediumHigh

  1. the, a
  2. a, an
  3. no article, a
  4. the, no article
  1. until
  2. up
  3. in
  4. to
  1. will be saved
  2. will have saved
  3. save
  4. am saved
  1. Speculate
  2. Disbelieve
  3. Prove
  4. Deliment
  1. Unfold
  2. Prolong
  3. Diminish
  4. Maneuver
  1. Cheap
  2. Usual
  3. Shocking
  4. Harmful
  1. Untrue
  2. Fresh
  3. Free
  4. Able
  1. CADB
  2. BADC
  3. CDBA
  4. ACDB
  1. The eyes of an owl give it a wide range of binocular vision, which means the owl can see objects in three dimensions and can judge distances in a similar way to humans.
  2. The eyes of an owl giving it a wide range of binocular vision, which means the owl can see objects in three dimensions and can judge distances in a similar way to humans.
  3. The eyes of an owl gives it a wider range of binocular vision, which means the owl can see objects in three dimensions and can judge distances in a similar way to humans.
  4. The eyes of an owl have given it a wide range of binocular vision, which means the owl can see objects in three dimensions and can judge distances in a similar way to humans.
  5. No error

Make sure that you don’t left anything for tomorrow.

  1. have left
  2. has left
  3. leave
  4. leaving
  5. no error

Maintaining healthy soil and improving crop growth is important for farmers worldwide. Many farmers use expensive and potentially harmful chemical fertilisers, making it difficult to manage nutrients. However, scientists are exploring eco-friendly alternatives, and nanotechnology is showing game-changer.

Nano-fertilisers are tiny particles that can significantly improve how plants absorb nutrients. Regular fertilisers, nano-fertilisers release nutrients slowly, preventing them from leaching into the groundwater. This not only improves nutrient efficiency but also benefits the environment. nano-fertilisers can help crops withstand harsh conditions. When combined with microorganisms, called nano-biofertilizers, they offer even more advantages.

While nano-fertilisers offer exciting opportunities for sustainable agriculture, it is essential to be cautious. Releasing too many nanomaterials into the environment and food chain could harm human health. Therefore, it is crucial to thoroughly study and understand these potential risks before widely adopting nano fertilisers in farming Biotechnological advancements are necessary to safely and electively use nanomaterial’s in agriculture

In conclusion, nano-fertilisers have great potential for improving plant nutrition and resilience in the face of climate change. However, careful consideration and further research are necessary to ensure their safety and effectiveness in enhancing agricultural practices.

  1. They can increase the need for water in agriculture.
  2. They can eliminate the need for chemical fertilisers
  3. They can improve the taste and quality of crops
  4. They can increase the resistance of crops to harsh condition.
  1. By increasing the crop yield
  2. By reducing the need for pesticides
  3. By drastically altering climate change
  4. By preventing nutrient from leaching into groundwater

(a) Invoice     (b) Sales Tax      (c) Octroi       (d) Quotation

  1. a
  2. b
  3. c
  4. d

1. Celebrations are observed the world over, but particularly in India, by throwing colour at one another.
2. Holi celebrates the arrival of spring and summer, as the dull winter breaks into a glow of colour under clear skies.
3. For Indians, the festival is a crucial part of the year, and collecting flowers and making colours begins late in winter.
4. Perhaps because the crops sown in autumn ripen under the newly golden sun, and so anticipation of glad times becomes only natural

  1. 3 2 4 1
  2. 2 4 1 3
  3. 2 3 4 1
  4. 2 1 4 3
  1. Vr/ (12V)
  2. Vr + V/12
  3. Vr – 12
  4. V/r-12
  1. 5
  2. 8
  3. 9
  4. 10

Assumptions:

I. The domestic market price of computer peripherals may go up near future

II. The domestic manufacturers may oppose the decision

  1. if only I is implicit;
  2. if only assumption II is implicit;
  3. If either I or II is implicit;
  4. if neither I nor II implicit
  5. if both I and II are implicit.

18. Statement: It is desirable to put the child in school at the age of 5 or so.

Assumptions:

I. At that age the child reaches appropriate level of development and is ready to learn.

II. The schools do not admit children after six years of age,

  1. if only I is implicit;
  2. if only assumption II is implicit;
  3. If either I or II is implicit;
  4. if neither I nor II implicit
  5. if both I and II are implicit.
  1. Immediate left
  2. Immediate right
  3. Second left
  4. Cannot be determined
  1. Red
  2. Green
  3. Blue
  4. Blue or Red
  1. Conspire: Neglect
  2. Invisible: Obvious
  3. Innocent: Witty
  4. Eternal: Endless

95, 115, 155, 175, 215, ?

  1. 255
  2. 235
  3. 240
  4. 260
  1. QVDK
  2. OLVK
  3. VKDQ
  4. DQVK
  1. I
  2. J
  3. L
  4. H
  1. 36
  2. 40
  3. 88
  4. None of these

Accenture Previous Year Question 2024 Technical Assesment

  1. format
  2. save
  3. edit
  4. print
  5. None of these
  1. TXT
  2. DOC
  3. WRD
  4. FIL
  1. On the vertical scroll bar’s top
  2. On the vertical scroll bar’s bottom
  3. The horizontal scroll bar’s left side
  4. the horizontal scroll bar’s right side
  1. domains
  2. protocols
  3. database
  4. extensions
  1. To save the document in a specific location
  2. To save a website’s URL for future reference
  3. To use the document for search
  4. To save alignments as it is.
  1. Algorithm
  2. Procedure
  3. Cipher
  4. Module
  1. Plain text
  2. Parallel text
  3. Encrypted text
  4. Decrypted text
  1. Legacy application data
  2. b. Mission-critical workloads
  3. Sensitive data
  4. All of the above
  1. Trust execution environments
  2. Zero-trust networks
  3. Fully homomorphic encryption
  4. Secure multiparty computation
  1. When applications must span hybrid architectures
  2. When applications are hosted solely in the cloud
  3. When an organization’s applications are all on premises
  4. When an organization uses a single cloud application

1. Integer p,q,r
Set p=6, q=5, r=6
p=(r+r)^q
for(each r from 4 to 5)
if(p(r-p))
q=(r^6)+r
Continue
End if
p=(q+8)&q
End for
Print p+q

Initialize p = 6, q = 5, and r = 6.
Calculate p = (r + r) ^ q, resulting in p = 9.
For r values from 4 to 5, check if p < q || (p + q) > (r – p).
If true, update q = (r ^ 6) + r for each r (resulting in q = 8 after the loop).
Print p + q, which gives 17.

2. Integer pp,qq,rr
Set pp=9, qq=8, rr=8
if ((pp+rr+8)<(4+qq+pp))
if ((rr+10+qq)<(6+rr))
qq=(qq+2)+pp
Else
qq=(rr+qq)+qq
End if
Else
if ((rr+qq-pp)<(5+rr))
pp=qq+qq
End if
End if
qq=(7+4)+pp
Print pp+qq+rr;

Initialize: pp = 9, qq = 8, rr = 8. 
Check if (pp + rr + 8) < (4 + qq + pp). 
(9 + 8 + 8) < (4 + 8 + 9), which is 25 < 21 (false). 
Check if (rr + qq – pp) < (5 + rr). 
(8 + 8 – 9) < (5 + 8), which is 7 < 13 (true). 
Since true, update pp = qq + qq→ pp = 8 + 8 = 16. 
Update qq = (7 + 4) + pp → qq = 11 + 16 = 27. 
Print pp + qq + rr = 16 + 27 + 8 = 51. 

3. Integer funn(Integer a, Integer b, Integer c)
b = (c^8) + c
for (each c from 4 to 7)
b = (c+11) & b
a = 11 & a
End for
return a+b

Initialize: a = 2, b = 7,c = 6.
Step 2: Calculate b = (c ^ 8) + c = (6 ^ 8) + 6 = 20.
Loop (Step 3-6): For c from 4 to 7:
Iteration 1: b = (4 + 11) & 20 = 4, a = 11 & 2 = 2
Iteration 2: b = (5 + 11) & 4 = 0, a = 11 & 2 = 2
Iterations 3-4: b remains 0, a remains 2.
Return: a + b = 2 + 0 = 2.

4. Integer a,b,c
Set a=5, b=2, c=7
if ((1-c-b)>(b-a))
if (2>a)
if ((b&c)<(5-b))
a=c^a
End if
b=9+b
Else
c=11&a
End if
b=(c+3)^b
End if
c=(b+c)+b
Print a+b+c

Initialize a = 5, b = 2, c = 7.
The condition ((1 – c – b) > (b – a)) evaluates to False, so we skip the nested updates for a and b.
Update b to (c + 3) ^ b, resulting in b = 8.
Update c to (b + c) + b, resulting in c = 23.
Finally, compute a + b + c = 5 + 8 + 23 = 36.

5. a=8,b=7,c=4
Integer funn(Integer a, Integer b, Integer c)
a=(b+b)&c
for(each c from 5 to 7)
b=3+c
b=(4+7)+b
a=(b&c)+c
End for
c=a+c
return a+b

Answer – 33
Initialize a = 8, b = 7, c = 4.
Update a to (b + b) & c, resulting in a = 4.
Loop through c from 5 to 7:
For c = 5: Update b to 19, then update a to 6.
For c = 6: Update b to 20, then update a to 10.
For c = 7: Update b to 21, then update a to 12.
After the loop, update c to a + c, resulting in c = 16.
Return a + b, which is 12 + 21 = 33.

Accenture Previous Year Question 2024 Coding Assesment

Input: 231
Output: Number in reverse order: 132

C++:

int reverseNumber(int num) {
int reversed = 0;
while (num > 0) {
reversed = reversed * 10 + (num % 10);
num /= 10;
}
return reversed;
}

JAVA:


int reverseNumber(int num) {
int reversed = 0;
while (num > 0) {
reversed = reversed * 10 + (num % 10);
num /= 10;
}
return reversed;
}

C++:

double calculateSI(double principal, double rate, double time) {
return (principal * rate * time) / 100;
}

JAVA:

double calculateSI(double principal, double rate, double time) {
return (principal * rate * time) / 100;
}

  • If the string s has more uppercase letters than lowercase letters, return it entirely in uppercase.
  • If the string s has more lowercase letters than uppercase letters, return it entirely in lowercase.

Examples:

“AbCdEfG” == “ABCDEFG”
“xYz” == “xyz”
“ABCabcXYZ” == “abcabcxyz”

JAVA:
String convertString(String str) {
int upperCount = 0, lowerCount = 0;
for (char c : str.toCharArray()) {
if (Character.isUpperCase(c)) upperCount++;
else if (Character.isLowerCase(c)) lowerCount++;
}
if (upperCount > lowerCount) {
return str.toUpperCase();
} else {
return str.toLowerCase();
}

C++:
string convertString(string str) {
int upperCount = 0, lowerCount = 0;
for (char c : str) {
if (isupper(c)) upperCount++;
else if (islower(c)) lowerCount++;
}
if (upperCount > lowerCount) {
for (char &c : str) {
if (islower(c)) {
c = toupper(c);
}
}
} else {
for (char &c : str) {
if (isupper(c)) {
c = tolower(c);
}
}
}
return str;
}